If n=24, (x-bar)=D34, and s=9, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. < µ <
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- We have presented a confidence interval (CI) for the difference, μ1 − μ2, between two population means. Interpret each confidence interval. 95% CI is from 15 to 20.If n=14, x(x-bar)=40, and s=10, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.Use the given data to construct a confidence interval for the population proportion p of the requested level. =x53 , =n68 , confidence level 80% Round the answers to at least three decimal places.If n=24, (x-bar)=44, and s=18, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.We have presented a confidence interval (CI) for the difference, μ1 − μ2, between two population means. Interpret each confidence interval. 99% CI is from −10 to 5.If n=27, (x-bar)=46, and s=19, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. <μ<If n=31, (x-bar)=36, and S3D3, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.The distribution of scores on a standardized test is approximately Normal with standard deviation of σσ = 22. If a sample of 150 students had a mean score of x¯x¯ = 74.3, use this to find a 99% confidence interval for the mean score of all students on this test. We are 99% confident that the the mean score of students on this test was in the interval What is the margin of error for your confidence interval? Margin of error =If n=-22, (x-bar)=50, and s-6, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.A researcher wants to make a 95% confidence interval for the population mean. She wants the maximum error of estimate to be within 4.8 of the population mean. The population standard deviation is 18.65. What would be the sample size the yield a maximum error of estimate within 4.8 of the population mean?If n=27, ¯xx¯(x-bar)=43, and s=14, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. < μμ <If n=26, ¯xx¯(x-bar)=45, and s=6, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. < μμ <SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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