If n=12, x=38, and s=18, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place. Can we conclude that the population mean is at least 32.42? Can we conclude that the population mean is no more than 47.08?

Q: If n = 20, a = 48, and s = 8, construct a confidence interval %3D at a 80% confidence level. Assume…

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Q: If n=32, ¯xx¯(x-bar)=31, and s=14, construct a confidence interval at a 95% confidence level. Assume…

A: Given: x¯=31n=32s=1495% confidence level

Q: If n=30, ¯xx¯(x-bar)=43, and s=16, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n = 10, ¯xx¯ = 43, and s = 8, construct a confidence interval at a 90% confidence level. Assume…

A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…

Q: If n = 15, 43, and s = 9, construct a confidence interval at a 98 % confidence level. Assume the…

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Q: If n=16, ¯xx¯(x-bar)=46, and s=12, construct a confidence interval at a 95% confidence level. Assume…

A: Given n=16 x=46 s=12 CL=95% Data is normally distributed

Q: If n=22, ¯xx¯(x-bar)=45, and s=4, construct a confidence interval at a 90% confidence level. Assume…

A: Ans -   Given the level of confidence interval   90 %                      Then   α = 1 - 0.90 =…

Q: If n=14, (x-bar)=37, and s=7, construct a confidence interval at a 98% confidence level. Assume the…

A: Given,n=14x¯=37s=7degrees of freedom(df)=n-1df=14-1=13α=1-0.98=0.02α2=0.01t0.01(13)=2.650     (from…

Q: If n=15, ¯xx¯(x-bar)=30, and s=2, construct a confidence interval at a 98% confidence level. Assume…

A: Given Sample size n = 15  degree of freedom = n-1 =14 x the level of confidence interval   98 %…

Q: If n = 22, ¯xx¯ = 36, and s = 14, construct a confidence interval at a 98% confidence level. Assume…

A: From the provided information, Sample size (n) = 22 Sample mean (x̄) = 36 Standard deviation (s) =…

Q: If n = 28, ¯xx¯ = 49, and s = 19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 28 Sample mean, x-bar = 49 Sample standard deviation, s = 19…

Q: construct a confidence interval at a 98% confidence level.

A: Given : n=29 , X-bar=39  , s=11  , α=0.02 Since , the population standard deviation (σ) is unknown.…

Q: If n = 16, 7 = 43, and s = 17, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n=19, ¯xx¯(x-bar)=37, and s=13, construct a confidence interval at a 99% confidence level. Assume…

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Q: Calculate the lower 95% confidence interval for the population mean. (round to the nearest tenth)…

A: From the provided information, n=31x=56σ2=15 Confidence level = 95%

Q: If n=22, ¯xx¯(x-bar)=46, and s=8, construct a confidence interval at a 98% confidence level. Assume…

A: It is given that mean and standard deviation are 46 and 8, respectively.

Q: If n=12, =49, and s=8, construct a confidence interval at a 80% confidence level. Assume the data…

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Q: n=31, ¯xx¯(x-bar)=30, and s=5, construct a confidence interval at a 98% confidence level. Assume the…

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Q: If n-19, ž(x-bar)-43, and s-8, construct a confidence interval at a 90% confidence level. Assume the…

A: Given: n = 19, x¯ = 43, s = 8 Confidence level = 90%

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given95% confidence interval N=361 x = 59.1 seconds. z= 4.9 SecondsFind the margin of error?

Q: If n=17, (x-bar)-45, and o =12, construct a confidence interval at a 80% confidence level. Assume…

A: Given X-bar=45 S=12 n=17

Q: If n=13, ¯x(x-bar)=44, and s=3, construct a confidence interval at a 99% confidence level. Assume…

A: Here, n is 13, x-bar is 44, and s is 3. Critical value: Using Excel formula…

Q: If n=19, ¯xx¯=40, and s=7, construct a confidence interval at a 99% confidence level. Assume the…

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Q: If n=15, ¯xx¯(x-bar)=40, and s=9, construct a confidence interval at a 98% confidence level. Assume…

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Q: If n=15, ¯xx¯(x-bar)=33, and s=19, construct a confidence interval at a 80% confidence level. Assume…

A: Given' :  sample mean xbar=33  sample size n=15  sample standard deviations s=14  then to find 80%…

Q: If n = 15, ¯xx¯ = 43, and s = 11, construct a confidence interval at a 98% confidence level. Assume…

A: Given that, The degree of freedom is, Critical values: The t-critical values for a two-tailed…

Q: If n=28, (x-bar)=45, and s-8, construct a confidence interval at a 99% confidence level. Assume the…

A: Given that.  Sample size n =28 Sample mean=45 Standard deviation =8

Q: If n=41, ¯x=39, and s=16, construct a confidence interval at a 99% confidence level. Assume the data…

A: Given that  Sample size (n) = 41 Sample mean (x¯) = 39 Sample standard deviation (s) = 16 Confidence…

Q: If n = 530 and X = 424, construct a 99% confidence interval for the population proportion, p. Give…

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Q: If n = 81, -45, and s to one decimal place. = 8, construct a confidence interval at a 90% confidence…

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Q: Out of 600 people sampled, 30 had children under the age of 18. Based on this, construct a 99%…

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Q: Which one of the following statements about confidence intervals is false?   Given the same sample…

A: In this case, we need to identify the false statement for confidence interval.

Q: If n=28, ¯x(x-bar)=32, and s=11, construct a confidence interval at a 95% confidence level. Assume…

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Q: A researcher wants to test if elementary school children spend less than 30 minutes per day on…

A: Given claim is A researcher  wants to test if the elementary school children spendless than 20…

Q: If n=13, ¯xx¯(x-bar)=37, and s=9, construct a confidence interval at a 80% confidence level. Assume…

A: Givenn =13x = 37s=9confidence interval =80%

Q: If n=30, (x-bar)=45, and s=13, construct a confidence interval at a 95% confidence level. Assume the…

A: We have given that,  Sample mean (x̄) = 45, sample size (n) = 30 and standard deviation (s) = 13…

Q: If n=29, x¯=48, and s=13, construct a confidence interval at a 90% confidence level. Assume the data…

A: The confidence level is 90%. Then the probability is 10%=100%-90%. The degrees of freedom is,…

Q: 15, ¯xx¯(x-bar)=39, and s=11, construct a confidence interval at a 95% confidence level. Assume the…

A: Sample size (n) =15 Sample mean (x¯)=39 Sample standard deviation (s)=11 Confidence level (C)=95%…

Q: If n=25, ¯x(x-bar)=31, and s=19, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size (n) = 25 Mean x̅ = 31 Standard deviation (s) = 19 Significance…

Q: If n = 15, ¯xx¯ = 36, and s = 12, construct a confidence interval at a 90% confidence level. Assume…

A: Given information- Sample size, n = 15 Mean systolic blood pressure, x-bar = 36 Sample standard…

Q: If n = 20, the sample mean = 250, SD = 15, SEM = 3.354, what is the confidence interval (using 95%…

A: The formula for a confidence interval for the population mean μ\mu when the population standard…

Q: f n=29, x¯(x-bar)=31, and s=8, construct a confidence interval at a 90% confidence level. Assume the…

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