If n is not an odd integer then square of n is not odd.Let P(n) be the predicate that is not an odd integer, and (n) be thepredicate that the square of n is not odd.For direct proof we should prove○‡n : (P(n) ⇒ Q(n))○Vn : (P(n) ⇒ Q(n))○Vn : (¬P(n) ⇒ ¬Q(n))○³n : (¬P(n) ⇒ ¬Q(n))Ovn: (¬Q(n) ⇒ ¬P(n))

For direct proof of the statement "if n is not an odd integer, then square of n is not odd"…

Answered: If n is not an odd integer then square…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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By dragging statements from the left column to the right column below, construct a valide proof of the statement: For all integers n, if 13n is even, then n is even. The correct proof will use 3 of the statements below. Statements to choose from: Let n be an arbitrary integer and assume n is odd. Let n be an arbitrary integer and assume n is even. Since 13 is odd and the product of an odd number and an even number is even, Let n be an arbitrary integer and assume 13n is even. 13n must be even Since 13 is odd and the product of odd numbers is odd, 13n must be odd. n must be even Since an even number divided by 13 must be even, Your Proof: Put chosen statements in order in this column and press the Submit Answers button.
(a) Consider the following proposition concerning an integer n > 2. If 3" – 1 is divisible by 4 then n is an even number. (i) Write down the contrapositive of this statement. (ii) Is the proposition true? Justify your answer!
Rewrite the following statements and their negations using quantifiers and symbols. Then, argue whether the statement or its negation is true by proving the statement or by finding a counterexample. (a) There is a rational number which is greater than its square root. i. Original statement: ii. Negation: iii. Which is true and why? (b) Each integer has the property that its square is less than or equal to its cube. i. Original statement: ii. Negation: iii. Which is true and why? (c) Every element in the set {0, 1,2} is greater than or equal to half of its square. i. Original statement: ii. Negation: iii. Which is true and why?
Apply De Morgan's law to the following expression to obtain an equivalent expression in which each negation sign applies directly to a predicate. (P(x) ^ (Q(x) v R(x))) O 3x (-P(x) v (¬Q(x) ^ ¬R(x))) -3x P(x) or 3x ¬(P(x) ^ Q(x)) O 3x (P(x) v (Q(x) ^ ¬R(x))) O None are equivalent.
Prove the argument by contraposition. For any integer n, if n² is odd then n is odd.
Suppose that P(n), Q(n) and R(n) are statements about the integer n. Let S(n) be the statement: “If P(n) is true then Q(n) and R(n) are both true." (a) The contrapositive of S(n) is the statement Olf Q (n) and R(n) are both true then P(n) is false. Olf Q (n) and R(n) are both true then P(n) is true. Olf at least one of Q(n) and R(n) is false then P(n) is false. Olf Q (n) and R(n) are both false then P(n) is false. Olf at least one of Q(n) and R(n) is false then P(n) is true. Olf P(n) is false then at least one of Q(n) and R(n) is false. Olf Q (n) and R(n) are both false then P(n) is true. ONone of the other answers. (b) The statement: "If Q (n) and R(n) are both true then P(n) is true." is OThe converse of S(n). OThe contrapositive of S(n). OThe converse of the contrapositive of S(n). ONone of the other answers.
Which of the following can be turned into a proof of the following argument: -(PAQ), P..¬Q. (i) (ii) (iii) ¬(P A Q) 1 |¬(P^Q) 1 1 2 P P n+1 ¬(PAQ) (ii) (ii) O (i) 2.
5. Consider the following: All numbers that end with a zero are divisible by 10. All numbers divisible by10 are divisible by 5. Therefore, every number that ends with a zero is divisible by 5.(a) Is this an argument? Why or why not? (b) Define your variables and write this argument as a sequence of premises in a form of implication,followed by a conclusion. (c) Is this argument valid? Prove using truth tables and by recognizing the rule of inference
Prove or refute the each of the following similar statements:(∀n∈N)(4 |n2→4 |n)(If the square of any natural number is divisible by 4, that number isdivisible by 4.)
Consider the statement: For all integers a and b, if a is even and b is a multiple of 3, then ab is a multiple of 6. Write the converse. Is it true? Prove or disprove using a formal proof. I need a formal proof
For propositions P(x) and Q(x) which of the following is equivalent to -Vx(P(x) VQ(x)) ? O3(-P(x) V-Q(x)) Ox(-P(x) ^ ¬Q(x)) O-3x (P(x) V Q(x)) O¬3x(-P(x) V ¬Q(x))
Consider the following conditional statement for a real number n: If n² is a rational number, then 2n − 1 < n². (a) Write the converse of the original statement: (b) Write the negation of the original statement: Write the contrapositive of the original statement: (d) Of (a)-(c), which is logically equivalent to the original statement? (e) Provide a value for n that makes the negation of the original statement (your answer for (b)) true and justify your answer.

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