If n = 300 and X = 60, construct a 95% confidence interval estimate for the population proportion. (State answers with four decimal places to the right of the decimal point.) O A. 0.1974 s ns 0.2026 using (60/300) ± CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)/300),300) O B. 0.1546 s as 0.2454 using (60/300) + CONFIDENCE.T(0.05,SQRT((60/300)*(240/300)),300) OC. 0.1547 s as 0.2453 using (60/300) + CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)),300) O D. 0.1999 s as 0.2001 using (60/300) ± CONFIDENCE.NORM(0.95,SQRT((60/300)"(240/300)/300),300)

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If n = 300 and X= 60, construct a 95% confidence interval estimate for the population proportion. (State answers with four decimal places to the right of the decimal point.)
O A. 0.1974 sns 0.2026 using (60/300) + CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)/300),300)
O B. 0.1546 sTs 0.2454 using (60/300) + CONFIDENCE.T(0.05,SQRT((60/300)*(240/300),300)
O C. 0.1547 STs 0.2453 using (60/300) + CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)),300)
O D. 0.1999 s ns 0.2001 using (60/300) + CONFIDENCE.NORM(0.95,SQRT(60/300)*(240/300)/300),300)
Transcribed Image Text:If n = 300 and X= 60, construct a 95% confidence interval estimate for the population proportion. (State answers with four decimal places to the right of the decimal point.) O A. 0.1974 sns 0.2026 using (60/300) + CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)/300),300) O B. 0.1546 sTs 0.2454 using (60/300) + CONFIDENCE.T(0.05,SQRT((60/300)*(240/300),300) O C. 0.1547 STs 0.2453 using (60/300) + CONFIDENCE.NORM(0.05,SQRT((60/300)*(240/300)),300) O D. 0.1999 s ns 0.2001 using (60/300) + CONFIDENCE.NORM(0.95,SQRT(60/300)*(240/300)/300),300)
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