If n + 1 integers are chosen from the set (1, 2, 3,..., 2n). where n is a positive integer, must at least one of them be even? To answer this question, let S = (1, 2, 3, necessary ✓ ✓ for at least one of the 2n), where n is a positive integer, and note that in S there are exactly elements of 7 to be even. Thus, the answer to this question is Yes v x odd integers. Since n + 1 is greater than the number of odd integers in T, it is

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