If mp₁, må₁, np₂, and nå2 are at least 10, we can use the large-sample test procedure with an approximately standard normal distribution. The variables m and n are the sample sizes of Brand A and Brand B, respectively, p₁ and ₂ are the sample proportions of non-contaminated chickens of Brand A and Brand B, respectively, and ₁=1 - p₁ and ₂ = 1 - ₂. Recall that 34 of 80 chickens from Brand A tested positive, so the number of non-contaminated chickens is 80 - 34 = 46 . The value of p₁ is the number of non-contaminated Brand A chickens divided by the total number of Brand A chickens, or p₁ = [ Calculate mp₁¹ mp₁ = 80( = Recall that 4₁ 1-p₁. Calculate mâ₁. ma₁ = 80(1-P₁) 80(1-0 = x ) We are told that 62 of 80 chickens from Brand B tested positive, so the number of non-contaminated chickens is 80 - 62 = chickens divided by the total number of chickens of Brand B, or p₂ = Calculate np₂. np₂ = 80( [ Calculate nâ2, where 4₂ = 1 - P₂. ną₂ = 80(1 - p₂) 80(1-0 = Referring to the values calculated above, the number of values less than or equal to 10 is -Select--- The value of p₂ is the number of non-contaminated Brand B so we ---Select--- use the large-sample test procedure for this data.

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If mp₁, mâ₁, np₂, and nâ, are at least 10, we can use the large-sample test procedure with an approximately standard normal distribution. The variables m and n are the sample sizes of Brand A and
Brand B, respectively, p₁ and 2 are the sample proportions of non-contaminated chickens of Brand A and Brand B, respectively, and ₁ = 1 - ₁ and ₂ = 1 - ₂. Recall that 34 of 80 chickens from
Brand A tested positive, so the number of non-contaminated chickens is 80 34 = 46
. The value of p₁ is the number of non-contaminated Brand A chickens divided by the total
number of Brand A chickens, or p₁ = |
Calculate mp₁.
mp₁ 80
=
np₂
Recall that ₁ = 1- P₁. Calculate mâ₁.
ma₁ = 80(1 - P₁)
80(1 –
=
nâ₂
=
We are told that 62 of 80 chickens from Brand B tested positive, so the number of non-contaminated chickens is 80 - 62 =
chickens divided by the total number of chickens of Brand B, or p₂ =
Calculate np₂.
= 80
X
* )
Calculate nâ2, where 4₂ = 1 - 0₂.
= 80(1 - p₂)
80(1
=
1 -
Referring to the values calculated above, the number of values less than or equal to 10 is
-Select---
The value of ₂ is the number of non-contaminated Brand B
so we ---Select--- use the large-sample test procedure for this data.
Transcribed Image Text:If mp₁, mâ₁, np₂, and nâ, are at least 10, we can use the large-sample test procedure with an approximately standard normal distribution. The variables m and n are the sample sizes of Brand A and Brand B, respectively, p₁ and 2 are the sample proportions of non-contaminated chickens of Brand A and Brand B, respectively, and ₁ = 1 - ₁ and ₂ = 1 - ₂. Recall that 34 of 80 chickens from Brand A tested positive, so the number of non-contaminated chickens is 80 34 = 46 . The value of p₁ is the number of non-contaminated Brand A chickens divided by the total number of Brand A chickens, or p₁ = | Calculate mp₁. mp₁ 80 = np₂ Recall that ₁ = 1- P₁. Calculate mâ₁. ma₁ = 80(1 - P₁) 80(1 – = nâ₂ = We are told that 62 of 80 chickens from Brand B tested positive, so the number of non-contaminated chickens is 80 - 62 = chickens divided by the total number of chickens of Brand B, or p₂ = Calculate np₂. = 80 X * ) Calculate nâ2, where 4₂ = 1 - 0₂. = 80(1 - p₂) 80(1 = 1 - Referring to the values calculated above, the number of values less than or equal to 10 is -Select--- The value of ₂ is the number of non-contaminated Brand B so we ---Select--- use the large-sample test procedure for this data.
Expert Solution
Step 1:-:

For brand A: 

Sample size or total number of Chickens is m= 80. 

Number of non-contaminated chickens are 80-34 =46.

p1^ = no. Of non-contaminated chickens/ Total number of Chickens

= 46/80

=0.575

 

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