Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question

Transcribed Image Text:### Question:
If \( m \angle 1 = 40^\circ \), find \( m \angle 2 \).
### Diagram:
The diagram displays two intersecting lines forming four angles labeled as 1, 2, 3, and 4.
### Answer Choices:
- \( \circ \) 140°
- \( \circ \) 60°
- \( \circ \) 40°
- \( \circ \) 50°
### Explanation of Diagram:
The intersecting lines create vertical angles. Vertical angles are congruent, meaning they have the same measure. In the diagram:
- \( \angle 1 \) and \( \angle 3 \) are vertical angles.
- \( \angle 2 \) and \( \angle 4 \) are vertical angles.
Thus, \( m \angle 1 = m \angle 3 \) and \( m \angle 2 = m \angle 4 \).
### Solution:
Given \( m \angle 1 = 40^\circ \), we find \( m \angle 2 \) using the properties of vertical angles and the fact that angles on a straight line sum up to \( 180^\circ \). Therefore:
- \( \angle 1 + \angle 2 = 180^\circ \)
- \( 40^\circ + m \angle 2 = 180^\circ \)
- \( m \angle 2 = 180^\circ - 40^\circ = 140^\circ \)
### Correct Answer:
- \( \circ \) 140°
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