If logical addresses are represented using m bits as shown below, where m=4 and n=2. What is the size of each frame in the main memory? Please explain why. Given the page table and the physical memory as shown on the right, what is the character in the corresponding physical address mapped from logical address 1010? Please explain why.
If logical addresses are represented using m bits as shown below, where m=4 and n=2. What is the size of each frame in the main memory? Please explain why. Given the page table and the physical memory as shown on the right, what is the character in the corresponding physical address mapped from logical address 1010? Please explain why.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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If logical addresses are represented using m bits as shown below, where m=4 and n=2.
What is the size of each frame in the main memory? Please explain why.
Given the page table and the physical memory as shown on the right, what is the character in the corresponding physical address mapped from logical address 1010? Please explain why.

Transcribed Image Text:The image illustrates the concept of paging in memory management. It consists of three main components: a logical address format, a page table, and a depiction of physical memory.
### Logical Address Format:
- **Page Number (p):**
- Size: \( m - n \) bits
- **Page Offset (d):**
- Size: \( n \) bits
This format shows how a logical address is divided into a page number and a page offset.
### Page Table:
The page table maps logical pages to physical frames. It is represented as a table with two columns:
- **Index (Logical Page Number):**
- 0
- 1
- 2
- 3
- **Frame Number (Physical Frame Address):**
- 0 maps to 6
- 1 maps to 5
- 2 maps to 2
- 3 maps to 1
### Physical Memory:
- Represented as a linear array with addresses increasing by a factor of 4, from 0 to 28.
- Each block (of size 4 units) is labeled with a set of letters:
- Address 0-3: Blank
- Address 4-7: m, n, o, p
- Address 8-11: j, k, l
- Address 12-15: Blank
- Address 16-19: e, f, g, h
- Address 20-23: i, j, k, l
- Address 24-27: a, b, c, d
- Address 28: Blank
This setup illustrates how logical pages are translated to physical memory frames using a page table, highlighting the relationship between logical and physical memory using paging.
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