If L is a line in 2-space or 3-space that passes through the points A and B, then the distance from a point P to the line L is equal to the length of the component of the vector AP that is orthogonal to the vector AB. B Use the method above to find the distance from the point P(-3, 1,6) to the line through A(1, 1,0) and B(-2,3,-4). NOTE: Enter the eract answer. Distance %3D

Q: 3y² - 2y-1 (-)-5y²- 2y +6

A:

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A: 64y2+7=32

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A:

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A: Refer to the we have to find the product of the -5 • -1/7 • 4/8

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A:

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A:

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A: -1+n=15

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A: For the solution follow the next step.

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A:

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A: The solution is, t = ±5√2  The detailed solution is as follows below:

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A:

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A: Given: The table x f(x) 1 4 2 1 3 2 4 6 5 3 6 5

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A: NOTE: Refresh your page if you can't see any equations. .

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A: This question can be solved using the concept of special integrals.

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A: Simply expand the summation and add all values after calculation.