If it takes 6.00 J of work to stretch a Hooke's-law spring 15.0 cm from its unstressed length, determine the extra work required to stretch it an additional 20.0 cm.
If it takes 6.00 J of work to stretch a Hooke's-law spring 15.0 cm from its unstressed length, determine the extra work required to stretch it an additional 20.0 cm.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:LABO
General Physics I - PHY195
D) P= F.V
01
36
56
OE)P=F.r
2-
If it takes 6.00 J of work to stretch a Hooke's-law spring 15.0 cm from its unstressed length, determine the extra work required to stretch it an additional 20.0 cm.
O A) 17 49 J
O B) 26.67 J
OC 23 60 J
O D) 15.80 J
OE 28 66 J
The moment of inertia solid cylinder or disk about an axis through the centre of mass is given as:
O A) None of these
O B)
Sonraki
ENG X
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Ps
Transcribed Image Text:General Physics | - PHY195
WUN
OD P=F.Vv
OEP=F.r
2-
If it takes 6.00 J of work to stretch a Hooke's-law spring 15.0 cm from its unstressed length, determine the extra work required to stretch it an additional 20.0 cm.
A) 17 49 J
O B) 26.67 J
C) 23 60 J
OD 15 80 J
E) 28 66 J
3-
The moment of inertia solid cylinder or disk about an axis through the centre of mass is given as:
OA None of these
Expert Solution
Step 1
Given Data:
Work Done to stretch spring from unstressed length to 15 cm = 6 Joule
We have to find out the additional work required to be done to stretch the spring to an additional 20 cm i.e. final extension of spring = 20 + 15 = 35 cm
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