If it is appropriate to do so, use the normal approximation to the p^ �^ -distribution to calculate the indicated probability: n=80,p=0.715= P( p̂ > 0.75) =
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A:
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: Customers arrives at service window at mean 3 hour (exponential distributed). compute the…
A:
Q: he mean and standard deviation of binomial distribution are 3 and √2 respectively, find the…
A: Given mean=3 np=3..(1) standard deviation=√2 variance=2 np(1-p)=2 3(1-p)=2 From the equation (1)…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: As per guidelines expert have to answer first question three subparts only dear student please…
Q: Consider two independent binomial experiments. In the first one, 86 trials had 51 successes. In the…
A: As per our guidelines we are suppose to answer only one question kindly post the remaining question…
Q: In the country of the United states of Heightlandia, the height measurements of ten-year-old…
A: Mean(μ)=56.3standard deviation(σ)=1.3
Q: If X is a random variable satisfying any e > 0, there exists a bounded ran P[X #
A: X is a random variable satisfying P(lXl<infinity)=1.
Q: The graph shows the probability density function for a car brand that has a mean fuel efficiency of…
A:
Q: The average fuel consumption of a car is 12 km per liter (per liter of gasoline used, the car…
A:
Q: Given a normal distribution with m = 84 and s^2 = 25, find the probability that X assumes a value…
A:
Q: Calculate using the normal approximation the probability that exatcle five people will have type O…
A: Given : There are 50% of the population that have type O blood and 16 people were selected.
Q: What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a…
A: Let X denote the number of miles (in thousands) that a car's tire will function before needing…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: The mean is 71 and the standard deviation is 10.
Q: In Ventura County, the height measurements of ten-year-old children are approximately normally…
A: Hi, we are supposed to answer three subparts at a time. Since you have not mentioned which question…
Q: What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a…
A: n = 15 mean = 66 sigma = 16
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: Note: Hey, since there are multiple subparts posted, we will answer first three subparts. If you…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: Let X be the number of miles (in thousands) that a car's tire will function before needing…
Q: Suppose the length of a music jingle has constant probability for all lengths between 60 and 75…
A: Here we need to find the distribution of music jingle. It has constant probability for all lengths…
Q: Given a normal distribution with m = 85 and s^2 = 25, find the probability that X assumes a value…
A:
Q: Q4/ The average on a statistics test was 78 with a standard deviation of 8. If the test scores are…
A:
Q: what is the probability of drawing a score at random from a normal distribution with a mean of…
A: Given , The random variable (X) follows normal distribution. Mean = μ = 101.99 Standard deviation =…
Q: The time taken by the truck to deliver the package is a random variable with a normal distribution…
A: Calculate the 90% confidence interval for μ
Q: Find the = value to the left of the mean so that 99.27% of the area under the distribution curve…
A: Find Z value P(Z<z)=99.27%
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A:
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: As per bartelby guideline expert have to answer first three subparts only dear student please upload…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: Therefore,
Q: If it is appropriate to do so, use the normal approximation to the p^ distribution to calculate…
A:
Q: What is the distribution of X? X ~ N(,) What is the distribution of ¯x¯? ¯x¯ ~ N(,) If a randomly…
A: Let X represents the number of miles (in thousands) that a car's tire will function before needing…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: b. Define X as the random variable of interest here, representing the number of miles (thousands)…
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A:
Q: Given a normal distribution with m = 83 and s^2 = 16, find the probability that X ... assumes a…
A: GivenMean(m)=83Variance(s2)=16standard deviation(s)=16=4
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A: Given that Mean=74 Standard deviation=19 Sample size=45 Note: According to bartleby experts…
Q: is 72 and the standard deviation is 19. Suppose that 47 randomly selected tires are tested. Round…
A:
P( p̂ > 0.75) =
Step by step
Solved in 4 steps with 15 images
- The average number of miles (in thousands) that a car's tire will function before needing replacement is 72 and the standard deviation is 14. Suppose that 12 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 68.9 and 74.4. For the 12 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 68.9 and 74.4. For part d), is the assumption that the distribution is normal necessary? YesNoA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 229.3-cm and a standard deviation of 1.5-cm. For shipment, 26 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 229-cm. P(M > 229-cm) = Enter your answer as a number accurate to 4 decimal places.The average number of miles (in thousands) that a car's tire will function before needing replacement is 65 and the standard deviation is 18. Suppose that 48 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 66.6 and 69.5. For the 48 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 66.6 and 69.5. For part d), is the assumption that the distribution is normal necessary?
- The length of a movie file that is available for streaming is modeled using the normal distribution shown below. The mean of the distribution is 170.5 min and the standard deviation is 19.9 min, In the figure, V is a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) 100 120 140 160 180 200 220 240 ( min)A simple random sample of 100 commute times is collected from the entire population of commuters in the United States. The mean of these 100 commute times is 45 minutes, with a standard deviation of about 30 minutes. mean = 45, standard deviation = 30, n = 100 Using the appropriate probability distribution, determine the critical value. Enter this value below to three decimal places. Calculate the margin of error using the critical value you determined in part (a). Enter this value below to three decimal places. Determine the confidence interval for the population mean μ\muμ. Express your answer in interval form. Interpret this confidence interval.Assume that the amount of weight that male college students gain during their freshman year are normally distributed with a. Mean of u= 1.2 kg and a standard deviation of o= 5.1 kg A. If 1 male college student is randomly selected, Find the probability that he gains between 0 and 3 kg during freshman year B. If 25 male college students are randomly selected find the probability that their mean weight gain during freshman year is between 0 and 3 kg why can the normal distribution be used on pet b even though the sample size does not exceed 30?
- The average number of miles (in thousands) that a car's tire will function before needing replacement is 72 and the standard deviation is 13. Suppose that 41 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 75 and 77.6. For the 41 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 75 and 77.6. For part d), is the assumption that the distribution is normal necessary? YesNoThe length of life time of a pesticide spray is normally distributed with a mean life timeis 12 months and standard deviation is 6 months. If this kind of spray is guaranteed for 10 months, find the probability of the sale that requires replacement.The average number of miles (in thousands) that a car's tire will function before needing replacement is 66 and the standard deviation is 19. Suppose that 44 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. What is the distribution of XX? XX ~ N(,) What is the distribution of ¯xx¯? ¯xx¯ ~ N(,) If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 65.8 and 68.1. For the 44 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 65.8 and 68.1. For part d), is the assumption that the distribution is normal necessary? YesNo
- Scores on an TOFEL for IT school candidates are normally distributed with μ = 140 and s = 14 What is the probability a candidate will likely score above 160? What percentage of candidates will likely score below 140?The noon-day temperature (in °C) in Ajax last winter can be represented by the normal distribution X~N( 6, 62). How often was it above - 3°C at noon in Ajax last winter? Make a sketch.