If In (x² - 15y) = x -y +5 and y(-4)= 1, find y'(-4) by implicit differentiation. 3'(-4)= An equation of the tangent line to the curve at the point (-4,1) is y =

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If In (x² - 15y) = x -y +5 and y(-4)= 1, find y'(-4) by implicit differentiation.
3'(-4)=
An equation of the tangent line to the curve at the point (-4,1) is
y =
Transcribed Image Text:If In (x² - 15y) = x -y +5 and y(-4)= 1, find y'(-4) by implicit differentiation. 3'(-4)= An equation of the tangent line to the curve at the point (-4,1) is y =
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