If in procedure B analysis of Zn2+ alone, 8.55 mL of 0.0100 M EDTA solution is used tofully titrate the Zn2+ content (FW = 65 g/moL) in the 10-mL of brass working solution, thenmmol of Zn2+ is present in the 10-mL solution. Therefore, the Zn2+concentration in the working solution ismM. Taken into the 10x dilution fromthe "stock solution", we can determine the concentration of the stock to bemM. Since there are total of 100-mL of stock solution, there are a total ofmmol of Zn in the washer, which ismg (3 s.f.).

Given: Volume of EDTA =8.55 mL Concentration of EDTA = 0.0100 M To determine: i) mmol of Zn2+

If in procedure B analysis of Zn2+ alone, 8.55 mL of 0.0100 M EDTA solution is used to fully titrate the Zn2+ content (FW = 65 g/moL) in the 10-mL of brass working solution, then mmol of Zn2+ is present in the 10-mL solution. Therefore, the Zn2+

If in procedure B analysis of Zn2+ alone, 8.55 mL of 0.0100 M EDTA solution is used to fully titrate the Zn2+ content (FW = 65 g/moL) in the 10-mL of brass working solution, then mmol of Zn2+ is present in the 10-mL solution. Therefore, the Zn2+

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

If in procedure B analysis of Zn2+ alone, 8.55 mL of 0.0100 M EDTA solution is used to
fully titrate the Zn2+ content (FW = 65 g/moL) in the 10-mL of brass working solution, then
mmol of Zn2+ is present in the 10-mL solution. Therefore, the Zn2+
concentration in the working solution is
mM. Taken into the 10x dilution from
the "stock solution", we can determine the concentration of the stock to be
mM. Since there are total of 100-mL of stock solution, there are a total of
mmol of Zn in the washer, which is
mg (3 s.f.).

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