If Im(z)#0 for all values of z and if f(z)=z^2+z+1 is a real valued function, then find its range O (-00,1/2] O (-00,1/3] O (-00,-1] O (-00,3/4] The domain of f(z) = z/(z+z) is Re (z) 0 Im (z) 0 Im (z)=0 Re (z)=0

Q: Show that f(g)x = x - 5x  Show f(g)x = x

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Q: Consider the following. f(x) = 8x – 3, g(x) = 1 - x Find (f - g)(x). The difference of two…

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Q: The one-to-one functions g and h are defined as follows. g = {(-7, -4), (2, 6), (3, 9), (6, 0)} h(x)…

A: The solution of the problem is given in the next steps.

Q: The range of f(x)= 2x2+5x-8 is [- 65/8, 0) O [-73/8,00) e [-10,00) [-17/2,0) [- 89/8,00) O…

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Q: x=[-5,-4,-3,-2,-1,0,1,2,3,4,5], A= [0.45    0.61    0.75    0.88    0.96   1    0.96    0.88    0.75…

A: Given: x=[-5,-4,-3,-2,-1,0,1,2,3,4,5], A= [0.45    0.61    0.75    0.88    0.96   1    0.96    0.88…

Q: USE +¹ (f(x)) =X a] if yinv b] the value of the value of d] f (3) if 3 = f¹ (2) 1 √x-7 to inv…

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Q: Find the domain of the composite function f-g. 1) f(x) · g(x) = x+91 45 X+5 A) (xx-5, x-10) C)…

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Q: Determine whether z^5-4iz^3+(1+8i)z+(17+(i)^(1/2)) is an entire function? Justify your answer

A: yes it is entire function.Explanation:Step 1:Step 2:Step 3:

Q: For the given functions f and g, find the requested function and state its domain. f(x) = *2; g(x):…

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Q: un 5 (2) = 2² - 82 and 9(2) = {-2₁" 22-5 x-1, x Evaluate(f/g) (7)

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Q: domain of f(x)=V9– x² is 1- (9,-9) 2- (-3,3) [-3,3] [9,-9] 2- 4-

A: Explanation of the answer is as follows

Q: The proper way to evaluate f(x + h) for the function f(x) = 3x²-x+4 is f(x + h) = 3(x+h)² - x +h+4…

A: Topic:- function

Q: known that the points (4, 7), (8, 11) and (14, 18) are on the graph of the function y = f(x). It is…

A: Given: (4,7),(8,11) and (14,18)   are on the graph of y=f(x)

Q: If the following is an injective function, what is the value of d+e+f? f={ (d+1, -4), (4,-4), (f^2 +…

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Q: what value of x is f(x)=6 f={(2,5), (6,5), (3,4), (-1,6)}

A: fx=6 & f=2, 5, 6, 5, 3, 4, -1, 6

Q: h(x) 36千 27 18- 9- -5 -4 3-2 -i 0/1 2 4 5-x 3 4 6- -18+ 27+ 36+ -45+

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