If I have a sample mean less than 30 at alpha= 0.05. What is the critical value using the Z table
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If I have a sample mean less than 30 at alpha= 0.05. What is the critical value using the Z table
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- qiiip1. answer only pls 6. what is the critical value 7. what is the computed value 8. compare the computed value and the critical value. what is the relationship between two values 9. what is the statistical decisionYou are performing a two-tailed matched-pairs test with 35 pairs of data.If α=0.1α=0.1, find the positive critical value, to two decimal places.2. Find the critical value using the Chi-Square Table for a = 0.10, n = 7, two- tailed.
- Show step by step 1 Simulate the failure times of 100 units randomly selected from a Weibull distributionwith characteristic life θ = 100 and shape parameter α = 3. Plot the histogram ofthese 100 data points and comment on this histogram. 2. Suppose the data of the last question came from a life testing but the test was stoppedat the 50-th failure. Re-organize the data set and re-plot the histogram. Compare thisplot with the previous plot and comment on these plots. Show step by step6. For a left-tailed test when n = 8 and a = 0.10 the critical value is %3D a. 1.397 b. -1.397 C. 1.415 d. -1.415The mean blood cholesterol level for all men aged 20 to 34 years is μ=188μ=188 mg/dl. We suspect that the mean for cross-country runners is lower. We take a random sample from all cross-country runners and measure the cholesterol level of each runner. We set α=0.10α=0.10 and correctly calculate a p−valuep−value of 0.08. Suppose someone else has additional information unavailable to us and it is known that IN REALITY cross-country runners actually do have lower cholesterol levels. Based on our calculations, what conclusion did we reach and did we make an error? The mean blood cholesterol level for all men aged 20 to 34 years is μ=188μ=188mg/dl. We suspect that the mean for cross-country runners is lower. We take a random sample from all cross-country runners and measure the cholesterol level of each runner. We set α=0.10α=0.10and correctly calculate a p−valuep−valueof 0.08. Suppose someone else has additional information unavailable to us and it is known that IN REALITY…
- You are performing a right-tailed test.If α=.01α=.01, find the critical value, to three decimal places.zα =The desired percentage of SiO₂ in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5 for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of SiO₂ in a sample is normally distributed with = 0.32 and that x = 5.23. (Use α = 0.05.) (a) Does this indicate conclusively that the true average percentage differs from 5.5? State the appropriate null and alternative hypotheses. Ho: μ = 5.5 H₂:μ> 5.5 O Ho: = 5.5 H₂¹ μ* 5.5 o Hoi H = 5,5 H₂:μ ≥ 5.5 Ho: μ = 5.5 H₂H5.5 X Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = -3.50 X X P-value = 0.0004 State the conclusion in the problem context. ⒸDo not reject the null hypothesis. There is not sufficient evidence to conclude that the true average percentage differs from the desired percentage. O Reject the null hypothesis. There is not sufficient…A random sample of 41 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.09 years, with sample standard deviation s = 0.83 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01. Solve the problem using the critical region method of testing (i.e., traditional method). (Round your answers to three decimal places.) test statitics= critical=
- So, if the chi-square is 4.29 and the critical value is 5.99. Do you accept or reject the Ho?If, in a sample of n=20 selected from a normal population, X = 54 and S = 12, what is your statistical decision if the level of significance, a is 0.01, the null hypothesis, Ho. is i = 50, and the alternative hypothesis, H, is #502 Click here to view page 1 of the table of the critical values of t. Click here to view page 2 of the table of the critical values oft. Determine the critical value(s). The critical value(s) is(are)| (Round to four decimal places as needed. Use a comma to separate answers as needed.)there is a claim that people living near major roads have higher blood levels of lead. 30 women living near the main road were randomly selected and the mean blood lead level was calculated as x̄1=15 and s1=5.0. in addition, 25 more women who did not live around the main road were sampled and calculated as x̄2=8.9 and s2=3.9. does this data obtained support the above claim? (test at α=0.05 significance level.)
