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If h(x) — За — — 1, j(x) k(x) = 21x? – 26x – 11 , show - 7x + 11 , and - - - - h(x) · j(x) = k(x).

If h(x) — За — — 1, j(x) k(x) = 21x? – 26x – 11 , show - 7x + 11 , and - - - - h(x) · j(x) = k(x).

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section3.2: Polynomial Functinos And Their Graphs
Problem 2E: Describe the end behavior of each polynomial. (a) y=x38x2+2x15 End behavior: y as x y as x (b)...
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Algebraically show that each of the given combinations are equivalent to the given functions. If h(x) = k(x) = 21x? – 26x – 11 , show h(x) · j(x) = k(x). — За — — 1, j(x) - 7x + 11 , and - - h(x) · j(x) = (| 21a² – 33x ×) · ( - 7х - 11 х|) 21x2 – 26x – 11 - - Is h(x) · j(x) equivalent to k(x)? ?
Transcribed Image Text:Algebraically show that each of the given combinations are equivalent to the given functions. If h(x) = k(x) = 21x? – 26x – 11 , show h(x) · j(x) = k(x). — За — — 1, j(x) - 7x + 11 , and - - h(x) · j(x) = (| 21a² – 33x ×) · ( - 7х - 11 х|) 21x2 – 26x – 11 - - Is h(x) · j(x) equivalent to k(x)? ?
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