If h(x) = f(x)g(x), we know h' = f'g+fg. Take another derivative and show that h" = f"g+2f'g' + fg". (Show means, do the computation and then notice that h" is indeed what it is supposed to be.) Show your work. Find a similar formula for h". Show your work.

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A: Differentiating the given function by using quotient rule, we get

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A: f(x)=xesinxf'(x)=esinx+xesinxcosx