If gravitation and frictional effects are negligible, which of the following relationships is true about the static pressure in sections A and C? PA Ps Pe Flow section A section B section C OPA = Pc because friction is assumed to be negligible and velocities are the same OPA > Pc because pressure drops in the direction of the flow even though friction is negligible OPA < Pc because pressure builds up through the smaller area in section B
If gravitation and frictional effects are negligible, which of the following relationships is true about the static pressure in sections A and C? PA Ps Pe Flow section A section B section C OPA = Pc because friction is assumed to be negligible and velocities are the same OPA > Pc because pressure drops in the direction of the flow even though friction is negligible OPA < Pc because pressure builds up through the smaller area in section B
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:If gravitation and frictional effects are negligible, which of the following relationships is true about the static pressure in sections A
and C?
PA
Pe
Ps
Flow
section A
section B
section C
OPA = Pc because friction is assumed to be negligible and velocities are the same
OPA > Pc because pressure drops in the direction of the flow even though friction is negligible
OPA < Pc because pressure builds up through the smaller area in section B

Transcribed Image Text:For the piping system shown below, water is flowing from left to right at steady-state and constant temperature. You may assume
the flow is frictionless.
The pipe diameter is larger in section A than section B. The diameters of sections A and C are the same.
If gravitation and frictional effects are negligible, which of the following relationships is true about the static pressure in sections A
and B?
Pc
Ps
Flow
section A
section B
section C
OPA< Pg because pressure builds up when mass is being pushed through a smaller area
OPA > Pg because pressure decreases as velocity increases at steady-state
OPA = Pg because friction is assumed to be negligible
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