If g(-1) = 2 and g'(-1) = 3 find h'(-1) for h(x) = [g(x)]° %3D %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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10

**Problem 10**

Given the following information:
- \( g(-1) = 2 \)
- \( g'(-1) = 3 \)

Find \( h'(-1) \) for the function:
\[ h(x) = [g(x)]^5 \]

**Explanation:**

To solve for \( h'(-1) \), we use the chain rule. Since \( h(x) = [g(x)]^5 \), the derivative \( h'(x) \) can be found as follows:

1. Differentiate the outside function: \( [g(x)]^5 \) becomes \( 5[g(x)]^4 \).

2. Multiply by the derivative of the inside function \( g(x) \), which is \( g'(x) \).

So, \( h'(x) = 5[g(x)]^4 \cdot g'(x) \).

Substitute \( x = -1 \):

\[ h'(-1) = 5[g(-1)]^4 \cdot g'(-1) \]

Plug in the given values:

\[ h'(-1) = 5[2]^4 \cdot 3 \]

\[ h'(-1) = 5 \cdot 16 \cdot 3 \]

\[ h'(-1) = 240 \]

Therefore, \( h'(-1) = 240 \).
Transcribed Image Text:**Problem 10** Given the following information: - \( g(-1) = 2 \) - \( g'(-1) = 3 \) Find \( h'(-1) \) for the function: \[ h(x) = [g(x)]^5 \] **Explanation:** To solve for \( h'(-1) \), we use the chain rule. Since \( h(x) = [g(x)]^5 \), the derivative \( h'(x) \) can be found as follows: 1. Differentiate the outside function: \( [g(x)]^5 \) becomes \( 5[g(x)]^4 \). 2. Multiply by the derivative of the inside function \( g(x) \), which is \( g'(x) \). So, \( h'(x) = 5[g(x)]^4 \cdot g'(x) \). Substitute \( x = -1 \): \[ h'(-1) = 5[g(-1)]^4 \cdot g'(-1) \] Plug in the given values: \[ h'(-1) = 5[2]^4 \cdot 3 \] \[ h'(-1) = 5 \cdot 16 \cdot 3 \] \[ h'(-1) = 240 \] Therefore, \( h'(-1) = 240 \).
Expert Solution
Step 1 Given :

g(-1)=2g'(-1)=3

We need to find value of :   h'(-1) 

given that h(x)=[g(x)]5

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