if f(x)=cospix, find the extact value of a such that f(1)-f(-1)/1-(-1)=cos a.

Q: What is the equation of the midline for the function f (x)? f (r) = 3 cos (r)- 2.5 Enter your answer…

A:

Q: A function f is defined by Ax + 5 f(x) 6x - 2 If f(1) = 4, find A.

A: Given: fx=Ax+56x-2  ……1   and, f1=4  ……2   To find: A

Q: If f(x) = 3x- x^2+2, find the value of: a.) f(0) b.) f(3) c.) f(-3) d.) f(-7) e.) f(3/2)

A: Given: fx=3x-x2+2 To find: a.) f(0) b.) f(3) c.) f(-3) d.) f(-7) e.) f32

Q: 3 s(1) =v° (v* + 2v=1) f(v) =

A:

Q: Sketch a graph of the function f(x) : 2 sin +1 6+ 4 -7 -6 -5 -4 -3 -2 -1 -1 1 2 3 -9 -8 4 5 -2 -3 -4…

A: Given: The function