If ƒ(x) = (x² + 4x + 8)², then f'(x) = f'(3) = places) (round to 3 decimal

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If \( f(x) = (x^2 + 4x + 8)^2 \), then

\[ f'(x) = \]

\[ f'(3) = \] (round to 3 decimal places)

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Transcribed Image Text:If \( f(x) = (x^2 + 4x + 8)^2 \), then \[ f'(x) = \] \[ f'(3) = \] (round to 3 decimal places) Question Help: - Video - Message instructor
Expert Solution
Step 1

f(x)=x2+4x+82

f'(x)=ddxx2+4x+82

 

Let, g(x)=x2+4x+8

So, the function can be written as:

f(x)=(g(x))^2

So,

f'(x)=ddx(g(x))^2

 

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