Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Problem Statement:**
If \( f(x) = \sin(x^3) \), find \( f'(x) \).
**Solution:**
The derivative \( f'(x) \) is given as \( 3x^2 \cos(x^3) \).
**Next step:**
Find \( f'(2) \).
**Explanation:**
To find the derivative of \( f(x) = \sin(x^3) \), we use the chain rule. The chain rule states that the derivative of a composite function \( f(g(x)) \) is \( f'(g(x)) \cdot g'(x) \).
1. Let \( u = x^3 \). Then, \( f(x) = \sin(u) \) and \( f'(u) = \cos(u) \).
2. The derivative of \( u = x^3 \) with respect to \( x \) is \( u' = 3x^2 \).
Therefore, \( f'(x) = \cos(x^3) \cdot 3x^2 = 3x^2 \cos(x^3) \).
Finally, to find \( f'(2) \), substitute \( x = 2 \) into the derivative:
\[ f'(2) = 3(2)^2 \cos((2)^3) = 3 \times 4 \cos(8) = 12 \cos(8). \]
The value of \( f'(2) \) is \( 12 \cos(8) \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3e51674d-3d29-4cb4-94ad-529601d10286%2F26ff444e-dc7f-43c3-881d-743e0d35a68a%2Fqyf7ik_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
If \( f(x) = \sin(x^3) \), find \( f'(x) \).
**Solution:**
The derivative \( f'(x) \) is given as \( 3x^2 \cos(x^3) \).
**Next step:**
Find \( f'(2) \).
**Explanation:**
To find the derivative of \( f(x) = \sin(x^3) \), we use the chain rule. The chain rule states that the derivative of a composite function \( f(g(x)) \) is \( f'(g(x)) \cdot g'(x) \).
1. Let \( u = x^3 \). Then, \( f(x) = \sin(u) \) and \( f'(u) = \cos(u) \).
2. The derivative of \( u = x^3 \) with respect to \( x \) is \( u' = 3x^2 \).
Therefore, \( f'(x) = \cos(x^3) \cdot 3x^2 = 3x^2 \cos(x^3) \).
Finally, to find \( f'(2) \), substitute \( x = 2 \) into the derivative:
\[ f'(2) = 3(2)^2 \cos((2)^3) = 3 \times 4 \cos(8) = 12 \cos(8). \]
The value of \( f'(2) \) is \( 12 \cos(8) \).
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