If f(x) = |x -- 5 is translated +2 units horizontally and -3 units vertically what would be the new equation? f'(x) = |x +2| – 8 A = l. f' (x) = |¤ – 3| – 7 B. %3D Oc f'(x) = |x + 3| – 7 C D. f'(x) = |æ – 2| – 8 %3D

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