If f(x) is continuous in the interval [-2, 1], ƒ(−2) = −4, and f(1) = -1, can we use the Intermediate Value Theorem to conclude that f(c) = 0 where -2 < c < 1? Select the correct answer below: Yes, the Intermediate Value Theorem guarantees that f(c) = 0. No, the Intermediate Value Theorem does not guarantee this conclusion, but f(c) = 0 could be true and cannot be ruled out.
If f(x) is continuous in the interval [-2, 1], ƒ(−2) = −4, and f(1) = -1, can we use the Intermediate Value Theorem to conclude that f(c) = 0 where -2 < c < 1? Select the correct answer below: Yes, the Intermediate Value Theorem guarantees that f(c) = 0. No, the Intermediate Value Theorem does not guarantee this conclusion, but f(c) = 0 could be true and cannot be ruled out.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Intermediate Value Theorem Application**
*Problem Statement:*
If \( f(x) \) is continuous in the interval \([-2, 1]\), \( f(-2) = -4 \), and \( f(1) = -1 \), can we use the Intermediate Value Theorem to conclude that \( f(c) = 0 \) where \(-2 < c < 1\)?
*Select the correct answer below:*
- ⦿ Yes, the Intermediate Value Theorem guarantees that \( f(c) = 0 \).
- ◯ No, the Intermediate Value Theorem does not guarantee this conclusion, but \( f(c) = 0 \) could be true and cannot be ruled out.
*Explanation:*
The Intermediate Value Theorem states that if a function \( f(x) \) is continuous on a closed interval \([a, b]\) and \( N \) is any number between \( f(a) \) and \( f(b) \), then there exists at least one number \( c \) in the interval \((a, b)\) such that \( f(c) = N \).
In this case:
- The function \( f(x) \) is continuous on \([-2, 1]\).
- \( f(-2) = -4 \) and \( f(1) = -1 \).
Since \( 0 \) lies between \( -4 \) and \( -1 \), by the Intermediate Value Theorem, there must exist some \( c \) in the interval \((-2, 1)\) such that \( f(c) = 0 \).
Therefore, the correct response is:
**Yes, the Intermediate Value Theorem guarantees that \( f(c) = 0 \).**
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Transcribed Image Text:---
**Intermediate Value Theorem Application**
*Problem Statement:*
If \( f(x) \) is continuous in the interval \([-2, 1]\), \( f(-2) = -4 \), and \( f(1) = -1 \), can we use the Intermediate Value Theorem to conclude that \( f(c) = 0 \) where \(-2 < c < 1\)?
*Select the correct answer below:*
- ⦿ Yes, the Intermediate Value Theorem guarantees that \( f(c) = 0 \).
- ◯ No, the Intermediate Value Theorem does not guarantee this conclusion, but \( f(c) = 0 \) could be true and cannot be ruled out.
*Explanation:*
The Intermediate Value Theorem states that if a function \( f(x) \) is continuous on a closed interval \([a, b]\) and \( N \) is any number between \( f(a) \) and \( f(b) \), then there exists at least one number \( c \) in the interval \((a, b)\) such that \( f(c) = N \).
In this case:
- The function \( f(x) \) is continuous on \([-2, 1]\).
- \( f(-2) = -4 \) and \( f(1) = -1 \).
Since \( 0 \) lies between \( -4 \) and \( -1 \), by the Intermediate Value Theorem, there must exist some \( c \) in the interval \((-2, 1)\) such that \( f(c) = 0 \).
Therefore, the correct response is:
**Yes, the Intermediate Value Theorem guarantees that \( f(c) = 0 \).**
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