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If f"(x) = cos(x); f(0) = 6, ƒ'(0) = -4, and f"(0) = -5, then what is f(x)? %3! Q3 5 – z? - f(x) = - cos(x) - -3x f(x) = - cos(x) – 3z + 6 f(x) = sin(x) – 5x² – 3r + 6 5 f(z) = - sin(z) – a - 3z + 6 %3D CS Scanned with CamScanner

If f"(x) = cos(x); f(0) = 6, ƒ'(0) = -4, and f"(0) = -5, then what is f(x)? %3! Q3 5 – z? - f(x) = - cos(x) - -3x f(x) = - cos(x) – 3z + 6 f(x) = sin(x) – 5x² – 3r + 6 5 f(z) = - sin(z) – a - 3z + 6 %3D CS Scanned with CamScanner

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Q3 Please provide correct answer with justification asap to get a upvote
If f"(x) = cos(): f(0) = 6, f'(0) = -4, and f"(0) = -5, then what is f(x)? Q3 f(z) = - cos(x) - z? - - 3r f(x) = - cos(x) – - 3x +6 f(x) = sin(2) – 5z? – 3r + 6 f(x) %3D%-sin(2)-요2-3z +6 CS Scanned with CamScanner
Transcribed Image Text:If f"(x) = cos(): f(0) = 6, f'(0) = -4, and f"(0) = -5, then what is f(x)? Q3 f(z) = - cos(x) - z? - - 3r f(x) = - cos(x) – - 3x +6 f(x) = sin(2) – 5z? – 3r + 6 f(x) %3D%-sin(2)-요2-3z +6 CS Scanned with CamScanner
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