If f(x) = 4x² ln(7x), then %3D f'(x) = f" (x) = f" (x) =

Q: f'(x) = ƒ'(e¹) = f(x) = -3x² Inx

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Q: Find f'(1) for f(x) = ln(3x² – 6x – 2) rounded to 3 decimal places. f'(1) = |6-6x/3x^2-6x-2

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Q: Find f'(- 2) for f(x) = In(5a? + 20x + 2) rounded to 3 decimal places. f'(- 2) =

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Q: The derivative of y = 2 ln ⁡ x − ln ⁡ x 3 is

A: The given function is, y=2lnx-lnx3

Q: If f(x) = 3x? – 2e", find: f'(x) = = (x),.

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Q: Find f'(x), f'"(x), and f""(x). f(x) = 4x? (2– 9x -3) f'(x)= f'"(x) =|

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Q: Differentiate   y = (x3 + 1) ln(x3 + 1)

A: Given, y=x3+1 lnx3+1

Q: Find f'(x) when f(x) = cos (4VT). %3D f'(x) =

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Q: Let (v 6x - 8 f(x) = ln %3D 5x + 4 f'(x) =

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Q: if f(x)=(4x+8)^-4 find f'(x) and f'(3).

A: Given:- f(x) = (4x+8)-4 To find:- f'(x) and f'(3)

Q: if f(x)=(4x+8)^−1 find f'(x) and f'(2)

A:

Q: Consider the function f(x) = (g(x)h(x))^2 and the following function values: f(5) = 1 g(5) = −1…

A: Given: f(x)=[g(x)h(x)]2f(5)=1g(5)=−1h(5)=2g'(5)=3h'(5)=4f'(5)=?

Q: Let f(x) = x + 12 f-'(x) = %3D 1.

A: Let's say y = f(x) A function g is said to be inverse of a function f, if g(y) = f(x) Procedure to…

Q: if f(x)=(5x+5)^−1 find f'(x) and f'(4).

A: Solving the problem by doing tge derivative and putting the value of x.

Q: If  h(x) =  sqrt of 7 + 6f(x)  where  f(4) = 7 and f '(4) = 2,  find h'(4).

A: Solution is given below..

Q: If f'(x) = 12r + 3z² and f(1) = 7, find f(x) . f(x) =

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Q: r(x) = 3x/4- x0.1/3 + 5/4x1.1 - 3 r'(x) =

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Q: f F(x)=ex , find f(ln(2))

A: fx=exfind f(ln(2)) Formula used elnea=a

Q: y=5ln(4x)x-1/2 find the derivative (d/dx)

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Q: Suppose f(x)=ln((ex2)/(x-6)7). Find f'(x)

A: We have to find f'(x).

Q: Find f''(x) f(x)=3x^2-13x-4/x^4

A: Given Find f''(x) f(x)=3x^2-13x-4/x^4

Q: Find g'(x) if g(x) %3D Зx е бх

A: Product rule of the derivative is, (uv)’=u’v+uv’ where u and v are the functions of x.

Q: f(x) = xV 3 - x² — х

A: Solution: The objective is to find the derivative of the given function

Q: If f(x)=(4x)^(ln x) how would you find f'(3)?

A: Obtain the derivative of the function as follows.

Q: 1 (d) Last week, Amy walked a median of 7.5 kilometres each day. 1 kilometre = 0.6 miles The table…

A:

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as: