If f(x) = 2 sin æ + 9 cos a, then f'(x) = f'(4) =|

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The given mathematical problem requires the determination of the first derivative of a function and its evaluation at a specific point.

**Problem Statement:**

Given the function: \( f(x) = 2 \sin x + 9 \cos x \), find the following:

1. The first derivative of the function, denoted as \( f'(x) \).
2. The value of the first derivative at \( x = 4 \), denoted as \( f'(4) \).

**Solution Steps:**

1. **Finding \( f'(x) \)**:
   - The first derivative of the function \( f(x) \) with respect to \( x \) is obtained by differentiating each term of the function.
   - The derivative of \( 2 \sin x \) is \( 2 \cos x \).
   - The derivative of \( 9 \cos x \) is \( -9 \sin x \).
   - Therefore, \( f'(x) = 2 \cos x - 9 \sin x \).

2. **Evaluating \( f'(4) \)**:
   - Substitute \( x = 4 \) into the first derivative:
   - \( f'(4) = 2 \cos 4 - 9 \sin 4 \).

In conclusion:

- \( f'(x) = \boxed{2 \cos x - 9 \sin x} \)
- \( f'(4) = \boxed{2 \cos 4 - 9 \sin 4} \)

This problem illustrates the application of differentiation on trigonometric functions and the evaluation of the derived function at a given point.
Transcribed Image Text:The given mathematical problem requires the determination of the first derivative of a function and its evaluation at a specific point. **Problem Statement:** Given the function: \( f(x) = 2 \sin x + 9 \cos x \), find the following: 1. The first derivative of the function, denoted as \( f'(x) \). 2. The value of the first derivative at \( x = 4 \), denoted as \( f'(4) \). **Solution Steps:** 1. **Finding \( f'(x) \)**: - The first derivative of the function \( f(x) \) with respect to \( x \) is obtained by differentiating each term of the function. - The derivative of \( 2 \sin x \) is \( 2 \cos x \). - The derivative of \( 9 \cos x \) is \( -9 \sin x \). - Therefore, \( f'(x) = 2 \cos x - 9 \sin x \). 2. **Evaluating \( f'(4) \)**: - Substitute \( x = 4 \) into the first derivative: - \( f'(4) = 2 \cos 4 - 9 \sin 4 \). In conclusion: - \( f'(x) = \boxed{2 \cos x - 9 \sin x} \) - \( f'(4) = \boxed{2 \cos 4 - 9 \sin 4} \) This problem illustrates the application of differentiation on trigonometric functions and the evaluation of the derived function at a given point.
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