- If f(r) = e² is a solution of xy" – (r + 1)/ + y = 0. Then, the general so (A) y = c1e² + c2e=z (B) y = c1e² + cz(z+ 1)e² (C) y = ce² + 2 (E) y = c1e² + c2(x+ 1)

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve 5
- If f(x) == e² is a solution of xy" – (r + 1)y/ + y = 0. Then, the general solution is
(A) y = c1e² + c2e=z
(B) y = c1c² + c2(x + 1)e²
(C) y = c1e² + C2IE²
(E) y = c1e² + c2(x + 1)
(D) y = cịe² + ca In(z)
6. Consider the differential equation ry" + v +v = 0. Suppose that {y1, m) is the fundarnental solution sec
and W[y1, y2](2) = }. Then, W[y1, y2}(x) is:
(A)
(B) 풍
(C) tổ:
(D)
(E) 궁
>
7. If f(x) is a particular solution of v" + 4y = 10 and g(z) is a particular solution of y" + 4y = -Ar. Ten,
a particular solution of y" + 4y = 5 + 8x is
(A) 2f(z) + }9(x)
(B) f(x) – 29(x) (C)}f(z) +2g(z) (D)-/(2) – 29(z)
(E)
8. A fundamental solution set for the differential equation z²y" – y – 3y = 0 is
(B) {e²=, e-2=}
(E) {r², z² In(z}}
(C) {r*, z-²}
(D) {r³, z-!}
(A) {e³*, e-²}
Transcribed Image Text:- If f(x) == e² is a solution of xy" – (r + 1)y/ + y = 0. Then, the general solution is (A) y = c1e² + c2e=z (B) y = c1c² + c2(x + 1)e² (C) y = c1e² + C2IE² (E) y = c1e² + c2(x + 1) (D) y = cịe² + ca In(z) 6. Consider the differential equation ry" + v +v = 0. Suppose that {y1, m) is the fundarnental solution sec and W[y1, y2](2) = }. Then, W[y1, y2}(x) is: (A) (B) 풍 (C) tổ: (D) (E) 궁 > 7. If f(x) is a particular solution of v" + 4y = 10 and g(z) is a particular solution of y" + 4y = -Ar. Ten, a particular solution of y" + 4y = 5 + 8x is (A) 2f(z) + }9(x) (B) f(x) – 29(x) (C)}f(z) +2g(z) (D)-/(2) – 29(z) (E) 8. A fundamental solution set for the differential equation z²y" – y – 3y = 0 is (B) {e²=, e-2=} (E) {r², z² In(z}} (C) {r*, z-²} (D) {r³, z-!} (A) {e³*, e-²}
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