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If FA = 40 kN and FB = 35 kN, determine the magnitude of the resultant force and specify the location of its point of application (x, y) on the slab.

If FA = 40 kN and FB = 35 kN, determine the magnitude of the resultant force and specify the location of its point of application (x, y) on the slab.

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P2-4 If FA = 40 kN and FB = 35 kN, determine the magnitude of the resultant force and specify the location of its point of application (x, y) on the slab. 0.75 m X 0.75 m 2.5 m 0.75 m FB 12.5 m 3 m 3 m 0.75 m 30 kN 90 KN FA 20 kN
Transcribed Image Text:P2-4 If FA = 40 kN and FB = 35 kN, determine the magnitude of the resultant force and specify the location of its point of application (x, y) on the slab. 0.75 m X 0.75 m 2.5 m 0.75 m FB 12.5 m 3 m 3 m 0.75 m 30 kN 90 KN FA 20 kN
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Step 1

Given, 

Advanced Physics homework question answer, step 1, image 1

Lets take point O as  origin (red colour)

FA = 40 kN at (XA = 2.5 m + 2.5 m + 0.75 m = 5.75 m, YA = 3 m+ 3m + 0.75 m = 6.75 m) = (5.75 m, 6.75 m)

FB = 35 kN at (XB = 2.5 m + 2.5 m + 0.75 m = 5.75 m, YB = 0.75 m) = (5.75 m, 0.75 m)

Take,

FC = 30 kN at (XC = 0.75 m, YC = 0.75 m) = (0.75 m, 0.75 m)

FD = 20 kN at (XD = 0.75 m, YD = 3 m+ 3m + 0.75 m = 6.75 m) = (0.75 m, 6.75m)

FE = 90 kN at (XE = 0.75 m + 2.5 m = 3.25 m, YE = 0.75 m + 3 m = 3.75 m) = (3.25 m, 3.75 m)

The resultant force = FR = FA+FB+FC+FD+FE = 215 kN

 

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