Answered: If E and F are two disjoint events with…

If E and F are two disjoint events with P(E) = 0.21 and P(F) = 0.23, what is P(E ∪ FC)? (Enter answer as a decimal with at least 2 correct decimal places)

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

If E and F are two disjoint events with P(E) = 0.21 and P(F) = 0.23, what is P(E ∪ F^C)? (Enter answer as a decimal with at least 2 correct decimal places)

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Expert Solution

Step 1: Introduce the given information

Given ,

P(E) = 0.21

P(F) = 0.23

We have to find , $P open parentheses E union F to the power of c close parentheses$

Using formulas,

$P open parentheses A intersection B to the power of c close parentheses equals P open parentheses A close parentheses minus P open parentheses A intersection B close parentheses$

And,

$P open parentheses A union B to the power of c close parentheses equals P open parentheses A close parentheses plus P open parentheses B to the power of c close parentheses minus P open parentheses A intersection B to the power of c close parentheses$

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