If dy = x²dx, what is the equation of y in terms of x if the curve passes through (1,1)? a. x2 – 3y + 3 = 0 b. x3 – 3y + 2 = 0 c. x³ + 3y + 2 = 0 d. x3 + 2y + 2 = 0
If dy = x²dx, what is the equation of y in terms of x if the curve passes through (1,1)? a. x2 – 3y + 3 = 0 b. x3 – 3y + 2 = 0 c. x³ + 3y + 2 = 0 d. x3 + 2y + 2 = 0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:6. If dy = x²dx, what is the equation of y in terms of x if the curve passes through
(1,1)?
а. х? — Зу + 3 %3D 0
b. x3 – 3y + 2 = 0
C. x³ + 3y + 2 = 0
d. x3 + 2y + 2 = 0
7. Find the equation of the curve at any point of which the tangent line has a slope of
2x.
а. х%3D —у? + с
b. y = -x² + c
С. х 3D у? + с
d. y = x² + c
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