If d8 is 04H, BX contains 1234H, and DS contains 2000H, what docs the instruction of MOV AX, d8[BX] do? (c)

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Not familiar with registers? indirect addressing method? What is the H? Explain the concept and answer below pls!
If d8 is 04H, BX contains 1234H, and DS contains 2000H, what does the
instruction of MOV AX, d8[BX] do?
(c)
ribed image text
Transcribed Image Text:If d8 is 04H, BX contains 1234H, and DS contains 2000H, what does the instruction of MOV AX, d8[BX] do? (c) ribed image text
(c)
Given Code is
MOV AX,d8[BX]
This is register indirect addressing method.
The effective address is found out by addition of the contents of d8 and Bx .The result is then added uil
DS register value to get actual address.The content of the obtained memory location is moved to AY
Given d8 contains 04H
BX contains 1234H
DS contains 2000H
Effective address = 2000H+1234H + 04H = 3128H
The code moves the content of this memory location into the accumulator AX.
Transcribed Image Text:(c) Given Code is MOV AX,d8[BX] This is register indirect addressing method. The effective address is found out by addition of the contents of d8 and Bx .The result is then added uil DS register value to get actual address.The content of the obtained memory location is moved to AY Given d8 contains 04H BX contains 1234H DS contains 2000H Effective address = 2000H+1234H + 04H = 3128H The code moves the content of this memory location into the accumulator AX.
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