if count[u] ==0] # Valid intial nodes S = [] # The result while Q: # While we have start nodes... u = Q.pop() # Pick one
if count[u] ==0] # Valid intial nodes S = [] # The result while Q: # While we have start nodes... u = Q.pop() # Pick one
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Redesign the topsort
def topsort(G):
count = dict((u, 0) for u in G) # The in-degree for each node
for u in G:
for v in G[u]:
count[v] += 1 # Count every in-edge
Q = [u for u in G if count[u] ==0] # Valid intial nodes
S = [] # The result
while Q: # While we have start nodes...
u = Q.pop() # Pick one
S.append(u) # Use it as first of the rest
for v in G[u]:
count[v] -= 1 # "Uncount" its out-edges
if count[v] == 0: # New valid start nodes?
Q.append(v) # Deal with them next
return S
Expert Solution
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Program Explanation
- Define function iterative_dfs with graph, start (Starting node) as the parameters.
- Define variable start which shall store the starting node
- Use while loop to choose the last node in every iteration with .pop(-1)
- Use nested if condition to find the path of the graph
- Call function and print the output
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Solved in 3 steps with 1 images
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