If Bismuth-210 has a half-life of 5.0 days and you started with 30.59 grams and you stopped the reaction at 6.25 hours and assume that 100% of the Bismuth-210 has been converted to Polonium- 210 which has a half-life of 140 days then now calculate how much Polonium-210 will be left after 27.50 days in grams. 21083BI - A + 2104Po and then 210 84P0 → B + 206 82Pb 0.9201 0.9898 O 1.0521 0.8624 1.0182

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If Bismuth-210 has a half-life of 5.0 days and you started with 30.59 grams and you stopped the
reaction at 6.25 hours and assume that 100% of the Bismuth-210 has been converted to Polonium-
210 which has a half-life of 140 days then now calculate how much Polonium-210 will be left after
27.50 days in grams.
21083BI
- A + 210
'84P0 and then
210
84PO
B + 206
82Pb
0.9201
0.9898
1.0521
0.8624
1.0182
0.8259
Transcribed Image Text:If Bismuth-210 has a half-life of 5.0 days and you started with 30.59 grams and you stopped the reaction at 6.25 hours and assume that 100% of the Bismuth-210 has been converted to Polonium- 210 which has a half-life of 140 days then now calculate how much Polonium-210 will be left after 27.50 days in grams. 21083BI - A + 210 '84P0 and then 210 84PO B + 206 82Pb 0.9201 0.9898 1.0521 0.8624 1.0182 0.8259
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