If (an)n is a sequence of positive real numbers that converges to 0, then the series Σan/√n converges. a. False, here is a counter-example: an = 1/n. b. True, because (an)neN is bounded (since it converges) and thus an/√n →0 by ALT. c. True, because an/√n →0 by ALT and thus, by n-th term test, an/√n converges. d. False, here is a counter-example: an = 1/√√n.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 55E
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If (an)n is a sequence of positive real numbers that converges to 0, then the series an/√n converges.
a. False, here is a counter-example: an
1/n.
b. True, because (an)neN is bounded (since it converges) and thus an/√n →0 by ALT.
c. True, because an/√n →0 by ALT and thus, by n-th term test, Σan/√n converges.
d. False, here is a counter-example: an = 1/√√n.
=
Transcribed Image Text:If (an)n is a sequence of positive real numbers that converges to 0, then the series an/√n converges. a. False, here is a counter-example: an 1/n. b. True, because (an)neN is bounded (since it converges) and thus an/√n →0 by ALT. c. True, because an/√n →0 by ALT and thus, by n-th term test, Σan/√n converges. d. False, here is a counter-example: an = 1/√√n. =
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