If an object has a moment of inertia 22 kg-m2 and rotates with an angular speed of 110 radians/s, what is its rotational kinetic energy? Krot = i

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If an object has a moment of inertia \( 22 \, \text{kg} \cdot \text{m}^2 \) and rotates with an angular speed of \( 110 \, \text{radians/s} \), what is its rotational kinetic energy?

\[ K_{\text{rot}} = \]

[Input Box] J

---

To solve for the rotational kinetic energy (\( K_{\text{rot}} \)), use the formula:

\[ K_{\text{rot}} = \frac{1}{2} I \omega^2 \]

where \( I \) is the moment of inertia and \( \omega \) is the angular speed.
Transcribed Image Text:**Current Attempt in Progress** If an object has a moment of inertia \( 22 \, \text{kg} \cdot \text{m}^2 \) and rotates with an angular speed of \( 110 \, \text{radians/s} \), what is its rotational kinetic energy? \[ K_{\text{rot}} = \] [Input Box] J --- To solve for the rotational kinetic energy (\( K_{\text{rot}} \)), use the formula: \[ K_{\text{rot}} = \frac{1}{2} I \omega^2 \] where \( I \) is the moment of inertia and \( \omega \) is the angular speed.
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