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If all the derivatives of f are defined, and f(3) = 2, ƒ' (3) = −1, f" (3) = 6, ƒ"" (3) = 15 The third degree Taylor of f about x = 3 is : ○2-(x − 3) + 3(x − 3)² + 4(x − 3)³ · 2x+6x² + 12x³ ○2-(x − 3) + 6(x − 3)² +12(x − 3)³ 0 ○ 2 − (x − 3) + 3(x − 3)² + 2(x − 3)³

If all the derivatives of f are defined, and f(3) = 2, ƒ' (3) = −1, f" (3) = 6, ƒ"" (3) = 15 The third degree Taylor of f about x = 3 is : ○2-(x − 3) + 3(x − 3)² + 4(x − 3)³ · 2x+6x² + 12x³ ○2-(x − 3) + 6(x − 3)² +12(x − 3)³ 0 ○ 2 − (x − 3) + 3(x − 3)² + 2(x − 3)³

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If all the derivatives of f are defined, and ƒ(3) = 2, ƒ¹ (3) = −1, ƒ″ (3) = 6, ƒ” (3) = 12. The third degree Taylor of f about x = 3 is 2 − (x − 3) + 3(x − 3)² + 4(x − 3)³ 2x+6x² + 12x³ 02 2 − (x − 3) + 6(x − 3)² + 12(x − 3)³ (x − 3) + 3(x − 3)² + 2(x − 3)³ 02-
Transcribed Image Text:If all the derivatives of f are defined, and ƒ(3) = 2, ƒ¹ (3) = −1, ƒ″ (3) = 6, ƒ” (3) = 12. The third degree Taylor of f about x = 3 is 2 − (x − 3) + 3(x − 3)² + 4(x − 3)³ 2x+6x² + 12x³ 02 2 − (x − 3) + 6(x − 3)² + 12(x − 3)³ (x − 3) + 3(x − 3)² + 2(x − 3)³ 02-
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