if A=[1 10 30 ; 5 -13] choose the correct code to get the matrix B =[15; 10 -1; 30 3]:B=A(3,2)O None of aboveB=A'O B=A(;,;)

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Answered: if A=[1 10 30 ; 5 -13] choose the…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Q1, Simplify the Boolean expression to its simplest form given here by using K map. You need to convert all the terms to standard SOP before K mapping. X = ABCD + ABCD + ABCD + ABCD + BCD + BCD + ABCD + ABD + ABCD CD 00 01 11 10 B 00 01 11 10 Q1 b) Repeat the simplification by using Boolean Identities.
1. Circle T (true) or F (false) for each of these Boolean equations. a) T F A +1 = A A + BC = (A + B)(B + C) A OB = AOB b) T F c) T F d) T F A(BC)=(AB)C e) A + B + C = A.B.C T F 2. Evaluate the following: Convert to hex: 11001001.10112 b) Convert to decimal: 110101.012 c) Convert to binary: 98.2510 d) Convert to decimal: 2A.416 3. Write the Boolean expression equivalent to the following logic circuit. Do not simplify! A D B 4. Draw the logic circuit realization of the following Boolean expression as stated. Do not simplify! f(A, B,C) = (A + B) + (B + C) 5. Write the complete truth table for the Boolean expression of 4 6. Simplify the following Boolean expression as far as possible, using the postulates and theorems of Boolean algebra. f(w, x, y) = wxy + wx + wỹ+ wxỹ 7. Simplify the following expression using the postulates and theorems of Boolean algebra. Eliminate all group complements. (АВС) (А + C)(А + C) 8. Given f(w, x, y, z) = I(0, 1,3,5, 13), a) Write the complete truth table…
ab'd' + abc + a'bd + a'b'c' + b'c'd' + a'c'd Of the 6 terms in the expression above, how many of them are redundant? (Enter a single numerical digit.)
QUESTION 5 Let N be a given positive integer, z [0],z[1],,z [N] be some given real numbers, and S be the system that transforms x [n] into y[n] = Zz[k]x[n-k]. k=0 Is the system S stable ? O Yes O No OIt depends IANA Click Save and Submit to save and submit. Click Save All Answers to save all answers.
Simplify the following expression using boolean algebra
What function is implemented with multiplexer?
1. Circle T (true) or F (false) for each of these Boolean equations. A +1 = A а) T F b) F A+ BC = (A + B)(B+C) T AOB = AOB c) F d) T F A(BC)=(AB)C e) T F A +B +C = A. B.C %3D 2. Evaluate the following: a) Convert to hex: 11001001.10112 b) Convert to decimal: 110101.012 c) Convert to binary: 98.2510 d) Convert to decimal: 2A.416
*4NE l Asiacell This code sorts the decimal places of a number consisting of ones, tens and hundreds, for example, when entering the number 583, it prints X=5, Y=8, Z=3 * 1-..... 2-...... 3-...... 1-Print "X="; a \ 100 2-Print "Y="; (a \ 100) \ 10 3-Print "Z="; (a Mod 100) \ 10 1-Print "X="; a \ 100 2-Print "Y="; (a Mod 100)*10 3-Print "Z="; (a Mod 100) * 10 1-Print "X="; a \ 100 2-Print "Y="; (a Mod 100) \ 10 3-Print "Z="; (a Mod 100) Mod 10 1-Print "X="; a \ 100 2-Print "Y="; (a \ O 100) mod10 3-Print "Z="; (a \ 100) Mod 10 1-Print "X="; a mod 100 2-Print "Y="; O (a Mod 100) \ 10 3-Print "Z="; (a Mod 100) Mod 10
Q4) Consider the following PCM transmitted signal 1 0 A 0 -A I I I 0 I I a. b. I 0 1 I 0 0 1 1 I 1 0 I 0 1 1 Which line code is used in this PCM transmitted signal If 3 bits quantization has been used. Sketch a possible sampled version of an analog signal that could have resulted in this PCM wave. I 1 1
Which one of the following is the property of sequence operator.
An 8 × 1 multiplexer has inputs A, B, and C connected to the selection inputs S2, S1, and So, respectively. The data inputs I, through I, are as follows: (a)* h= Iz= I;= 0; Iz= Is= 1; 1,= I4= D; and I6= D'. (b) 1 = I½ = 0; I3 = I, = 1; I4 = I5 = D; and I, = I6 = D’. Determine the Boolean function that the multiplexer implements.

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if A=[1 10 30 ; 5 -13] choose the correct code to get the matrix B =[15; 10 -1 ; 30 3]: B=A(3,2) O None of above B=A' O B=A(;,;)