If a student has 100.0 mL of a 0.100 M solution of propanoic acid and 100.0 mL of a 0.0850 M solution of sodium propanoate, the volume of propanoic acid solution he will have to mix with the sodium propanoate solution to prepare 85.0 mL of a buffer solution with a pH of 5.8 would be: (the pka for propanoic acid is 4.87) Show steps please
If a student has 100.0 mL of a 0.100 M solution of propanoic acid and 100.0 mL of a 0.0850 M solution of sodium propanoate, the volume of propanoic acid solution he will have to mix with the sodium propanoate solution to prepare 85.0 mL of a buffer solution with a pH of 5.8 would be: (the pka for propanoic acid is 4.87) Show steps please
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:If a student has 100.0 mL of a 0.100 M solution of propanoic acid and 100.0 mL of a 0.0850 M solution of sodium
propanoate, the volume of propanoic acid solution he will have to mix with the sodium propanoate solution to prepare
85.0 mL of a buffer solution with a pH of 5.8 would be:
(the pka for propanoic acid is 4.87)
Show steps please
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