If a stone is dropped from the top of a tower with initial release velocity equal to zero, it falls a distance d in time t given by d = ½ gt2 where g is acceleration due to gravity (g = 9.8 m/s2). Its speed v at time t is given by v = gt. Suppose you go to the top of a tower and drop a stone. It hits the ground after 4.5 seconds. By how much does it drop in 1 second? How much is its displacement between 1 s and 2 s? What is the height of the tower? Drop = 14.7 m, Displacement = 4.9 m, Height = 19.6 m Drop = 4.9 m, Displacement = 14.7 m, Height = 99 m Drop = 4.9 m, Displacement = 14.7 m, Height = 19.6 m

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Chapter1: Units, Trigonometry. And Vectors
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If a stone is dropped from the top of a tower with initial release velocity equal to zero, it falls a distance d in time t given by d = ½ gt2 where g is acceleration due to gravity (g = 9.8 m/s2). Its speed v at time t is given by v = gt. Suppose you go to the top of a tower and drop a stone. It hits the ground after 4.5 seconds. By how much does it drop in 1 second? How much is its displacement between 1 s and 2 s? What is the height of the tower?

  1. Drop = 14.7 m, Displacement = 4.9 m, Height = 19.6 m
  2. Drop = 4.9 m, Displacement = 14.7 m, Height = 99 m
  3. Drop = 4.9 m, Displacement = 14.7 m, Height = 19.6 m
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