If a solution was created by mixing 250 mL of pure isopropyl alcohol with enoughwater to make 1.00 L of solution. What is the % (v/v) concentration?O 2.5 %20 %25 %O 70 % Aluminum reacts with chlorine to form aluminum chloride. The equation for thisreaction is 2 AlI(s) + 3 Cl2(g) → 2 AICI3(s). What is the percentage yield for a reactionin which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g ofaluminum chloride? Use the molar mass values given here.MAI = 26.9815 g/mol%3DMCl2 = 70.9064 g/mol%3DMAICI3 = 133.3411 g/mol%3D66.8 %100.699.4 %49.7 %

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If a solution was created by mixing 250 mL of pure isopropyl alcohol with enough water to make 1.00 L of solution. What is the % (v/v) concentration? 2.5 % 20 % 25 % 70 %

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

If a solution was created by mixing 250 mL of pure isopropyl alcohol with enough
water to make 1.00 L of solution. What is the % (v/v) concentration?
O 2.5 %
20 %
25 %
O 70 %

Aluminum reacts with chlorine to form aluminum chloride. The equation for this
reaction is 2 AlI(s) + 3 Cl2(g) → 2 AICI3(s). What is the percentage yield for a reaction
in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of
aluminum chloride? Use the molar mass values given here.
MAI = 26.9815 g/mol
%3D
MCl2 = 70.9064 g/mol
%3D
MAICI3 = 133.3411 g/mol
%3D
66.8 %
100.6
99.4 %
49.7 %

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