If a solution containing 66.97 g of mercury(II) acetate is allowed to react completely with a solution containing 10.872 g of sodium sulfide, how many grams of solid precipitate will be formed? mass: How many grams of the reactant in excess will remain after the reaction? mass: Assuming complete precipitation, how many moles of cach ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. Hg²+: mol CH,0;: mol Na*: mol s²- mol

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Assuming complete precipitation, how many
moles of each ion remains in solution? If an
ion is no longer in solution, enter a zero (0) for
the number of moles. I submitted something
similar earlier, mol for C2H3O2- was wrong.
Having trouble figuring it out.
C2H3Ò2-
If a solution containing 66.97 g of mercury(II) acetate is allowed to react completely with a solution containing 10.872 g of
sodium sulfide, how many grams of solid precipitate will be formed?
mass:
How many grams of the reactant
excess will remain after the reaction?
mass:
Assuming complete precipitation, how many moles of each ion remain
(0) for the number of moles.
solution?
an ion is no longer in solution, enter a zero
Hg2+:
mol
CH,0;:
mol
Na*:
mol
s2-:
mol
Transcribed Image Text:Assuming complete precipitation, how many moles of each ion remains in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. I submitted something similar earlier, mol for C2H3O2- was wrong. Having trouble figuring it out. C2H3Ò2- If a solution containing 66.97 g of mercury(II) acetate is allowed to react completely with a solution containing 10.872 g of sodium sulfide, how many grams of solid precipitate will be formed? mass: How many grams of the reactant excess will remain after the reaction? mass: Assuming complete precipitation, how many moles of each ion remain (0) for the number of moles. solution? an ion is no longer in solution, enter a zero Hg2+: mol CH,0;: mol Na*: mol s2-: mol
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