If a solution containing 107.7 g of mercury(II) chlorate is allowed to react completely with a solution containing 17.796 g of sodium sulfide, how many grams of solid precipitate will be formed? ***Please be NEAT with all the answer. **** 53.5118 mass: How many grams of the reactant in excess will remain after the reaction? 23.9 mass: Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. 0.13 H mol Incorrect 212.9 CIO: mol Incomect 0.2280 Na mol s- mol

If a solution containing 107.7 g of mercury(II) chlorate is allowed to react completely with a solution containing 17.796 g of sodium sulfide, how many grams of solid precipitate will be formed? *Please be NEAT with all the answer. ** 53.5118 mass: How many grams of the reactant in excess will remain after the reaction? 23.9 mass: Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a zero (0) for the number of moles. 0.13 H mol Incorrect 212.9 CIO: mol Incomect 0.2280 Na mol s- mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

If a solution containing 107.7 g of mercury(II) chlorate is allowed to react completely with a solution containing 17.796 g of
sodium sulfide, how many grams of solid precipitate will be formed?
***Please be NEAT with all the answer.****
53.5118
mass:
g
How many grams of the reactant in excess will remain after the reaction?
23.9
mass:
g
Assuming complete precipitation, how many moles of each ion remain in solution? If an ion is no longer in solution, enter a
zero (0) for the number of moles.
0.13
Hg²+:
mol
Incorrect
212.9
CIO3:
mol
Incorrect
0.2280
Na+:
mol
s2 -:
mol

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