If a seed is planted, it has a 75% chance of growing into a healthy plant. If 10 seeds are planted, what is the probability that exactly 3 don't grow?
If a seed is planted, it has a 75% chance of growing into a healthy plant. If 10 seeds are planted, what is the probability that exactly 3 don't grow?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### Probability of Seed Growth
If a seed is planted, it has a 75% chance of growing into a healthy plant.
If 10 seeds are planted, what is the probability that exactly 3 don't grow?
[Input Box for Answer]
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### Explanation
Given a 75% chance of a seed growing into a healthy plant, it follows that there is a 25% chance that a seed won't grow.
To solve for the probability that exactly 3 out of 10 seeds do not grow, you would use the binomial probability formula:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
where:
- \( n \) is the total number of trials (seeds planted)
- \( k \) is the number of successful outcomes (seeds not growing in this case)
- \( p \) is the probability of a success on an individual trial (probability that a seed does not grow)
- \( \binom{n}{k} \) is the binomial coefficient
In this problem:
- \( n = 10 \)
- \( k = 3 \)
- \( p = 0.25 \)
Thus, the probability that exactly 3 out of 10 seeds do not grow would be:
\[ P(X = 3) = \binom{10}{3} (0.25)^3 (0.75)^7 \]
### Calculation Steps:
1. Calculate the binomial coefficient \( \binom{10}{3} \).
2. Raise 0.25 to the power of 3.
3. Raise 0.75 to the power of 7.
4. Multiply all these values together to get the probability.
Make sure to insert your answer in the provided input box.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a3586c7-75e0-478e-8b93-fa570f1e3b86%2Feb809f9c-cc9b-4683-b308-a741855cf2b7%2Fodbkxqh_processed.png&w=3840&q=75)
Transcribed Image Text:### Probability of Seed Growth
If a seed is planted, it has a 75% chance of growing into a healthy plant.
If 10 seeds are planted, what is the probability that exactly 3 don't grow?
[Input Box for Answer]
---
### Explanation
Given a 75% chance of a seed growing into a healthy plant, it follows that there is a 25% chance that a seed won't grow.
To solve for the probability that exactly 3 out of 10 seeds do not grow, you would use the binomial probability formula:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
where:
- \( n \) is the total number of trials (seeds planted)
- \( k \) is the number of successful outcomes (seeds not growing in this case)
- \( p \) is the probability of a success on an individual trial (probability that a seed does not grow)
- \( \binom{n}{k} \) is the binomial coefficient
In this problem:
- \( n = 10 \)
- \( k = 3 \)
- \( p = 0.25 \)
Thus, the probability that exactly 3 out of 10 seeds do not grow would be:
\[ P(X = 3) = \binom{10}{3} (0.25)^3 (0.75)^7 \]
### Calculation Steps:
1. Calculate the binomial coefficient \( \binom{10}{3} \).
2. Raise 0.25 to the power of 3.
3. Raise 0.75 to the power of 7.
4. Multiply all these values together to get the probability.
Make sure to insert your answer in the provided input box.
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