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If a pivot point of a scale is located one quarter the length of the scale with 50.0 kg rest on the short-side of the scale, how much mass would be needed to achieve mechanical equilibrium on the long-side of the scale?

If a pivot point of a scale is located one quarter the length of the scale with 50.0 kg rest on the short-side of the scale, how much mass would be needed to achieve mechanical equilibrium on the long-side of the scale?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question 5 please

Chapter 7 PHYS 203: Fundamentals of Physics 4. A porch swing that is 1.50 m long and weighs 50.0 N has a dog-that weighs 23.2 N-0.3 m from the left end and a 110.1 N person 0.4 m from the opposite end of the dog. What force must each rope support at each end of the swing? 5. If a pivot point of a scale is located one quarter the length of the scale with 50.0 kg rest on the short-side of the scale, how much mass would be needed to achieve mechanical equilibrium on the long-side of the scale?
Transcribed Image Text:Chapter 7 PHYS 203: Fundamentals of Physics 4. A porch swing that is 1.50 m long and weighs 50.0 N has a dog-that weighs 23.2 N-0.3 m from the left end and a 110.1 N person 0.4 m from the opposite end of the dog. What force must each rope support at each end of the swing? 5. If a pivot point of a scale is located one quarter the length of the scale with 50.0 kg rest on the short-side of the scale, how much mass would be needed to achieve mechanical equilibrium on the long-side of the scale?
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