If a pdf of Y is ƒ(y)={1-|>| ||S1' />1 find and graph F(y).

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Chapter1: Combinatorial Analysis
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### Problem Statement

If a probability density function (pdf) of \( Y \) is 

\[
f(y) = 
\begin{cases} 
0, & |y| > 1 \\ 
1 - |y|, & |y| \leq 1 
\end{cases}
\]

find and graph \( F(y) \).

### Explanation

**Probability Density Function (pdf):**

- The function \( f(y) \) describes the probability density function for the random variable \( Y \).
- For \(|y| > 1\), the pdf is zero, indicating that values of \( Y \) outside this range have a probability density of zero.
- For \(|y| \leq 1\), the pdf is given by \(1 - |y|\), a linear function that forms a triangle with base endpoints at \( y = -1 \) and \( y = 1 \), peaking at \( y = 0 \).

**Cumulative Distribution Function (CDF):**

The cumulative distribution function \( F(y) \) is obtained by integrating the pdf:

- For \( y < -1 \), \( F(y) = 0 \).
- For \(-1 \leq y \leq 0\), calculate the integral from \(-1\) to \( y \) of \(1 - (-t)\).

\[ F(y) = \int_{-1}^{y} (1 - (-t)) \, dt = \int_{-1}^{y} (1 + t) \, dt \]

Calculate the integral to find \( F(y) \) in this interval.

- For \( 0 < y \leq 1\), calculate the integral from \(-1\) to \( 0\) and then add the integral from \(0\) to \( y \) of \(1 - t\).

\[ F(y) = \int_{-1}^{0} (1 + t) \, dt + \int_{0}^{y} (1 - t) \, dt \]

Continue calculating to find the complete CDF \( F(y) \).

- For \( y > 1 \), \( F(y) = 1 \), as all probabilities sum to 1.

**Graph:**

- Graph \( F(y) \), which will be a continuous, non-decreasing function.
- The graph of the pdf
Transcribed Image Text:### Problem Statement If a probability density function (pdf) of \( Y \) is \[ f(y) = \begin{cases} 0, & |y| > 1 \\ 1 - |y|, & |y| \leq 1 \end{cases} \] find and graph \( F(y) \). ### Explanation **Probability Density Function (pdf):** - The function \( f(y) \) describes the probability density function for the random variable \( Y \). - For \(|y| > 1\), the pdf is zero, indicating that values of \( Y \) outside this range have a probability density of zero. - For \(|y| \leq 1\), the pdf is given by \(1 - |y|\), a linear function that forms a triangle with base endpoints at \( y = -1 \) and \( y = 1 \), peaking at \( y = 0 \). **Cumulative Distribution Function (CDF):** The cumulative distribution function \( F(y) \) is obtained by integrating the pdf: - For \( y < -1 \), \( F(y) = 0 \). - For \(-1 \leq y \leq 0\), calculate the integral from \(-1\) to \( y \) of \(1 - (-t)\). \[ F(y) = \int_{-1}^{y} (1 - (-t)) \, dt = \int_{-1}^{y} (1 + t) \, dt \] Calculate the integral to find \( F(y) \) in this interval. - For \( 0 < y \leq 1\), calculate the integral from \(-1\) to \( 0\) and then add the integral from \(0\) to \( y \) of \(1 - t\). \[ F(y) = \int_{-1}^{0} (1 + t) \, dt + \int_{0}^{y} (1 - t) \, dt \] Continue calculating to find the complete CDF \( F(y) \). - For \( y > 1 \), \( F(y) = 1 \), as all probabilities sum to 1. **Graph:** - Graph \( F(y) \), which will be a continuous, non-decreasing function. - The graph of the pdf
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