### Solving Friction Problems**Problem Statement:**If a force of 30 N is required to move a mass of 35 kg on a flat surface horizontally at a constant velocity, what will be the coefficient of friction?**Options:**(a) 0.067 (b) 0.087 (c) 0.098 (d) 0.092 **Explanation:**To solve this problem, we need to use the formula for the coefficient of friction (μ):\[ \mu = \frac{F}{N} \]Where: - \( F \) is the force required to move the object (30 N)- \( N \) is the normal forceThe normal force (N) is equal to the gravitational force on the object, which is the weight of the object. The weight can be calculated using:\[ N = mg \]Where: - \( m \) is the mass (35 kg)- \( g \) is the acceleration due to gravity (9.8 m/s²)Calculate \( N \):\[ N = 35 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 343 \, \text{N} \]Now, calculate the coefficient of friction \( \mu \):\[ \mu = \frac{30 \, \text{N}}{343 \, \text{N}} ≈ 0.0875 \]By rounding, we find that the coefficient of friction is closest to option (b) 0.087.**Answer:**(b) 0.087

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If a force of 30 N is required to move a mass of 35 kg on a flat surface horizontally at a constant velocity, what will be the coefficient of friction? (a) 0.067 (b) 0.087 (c) 0.098 (d) 0.092

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Question

### Solving Friction Problems

**Problem Statement:**
If a force of 30 N is required to move a mass of 35 kg on a flat surface horizontally at a constant velocity, what will be the coefficient of friction?

**Options:**
(a) 0.067
(b) 0.087
(c) 0.098
(d) 0.092

**Explanation:**

To solve this problem, we need to use the formula for the coefficient of friction (μ):

\[ \mu = \frac{F}{N} \]

Where:
- \( F \) is the force required to move the object (30 N)
- \( N \) is the normal force

The normal force (N) is equal to the gravitational force on the object, which is the weight of the object. The weight can be calculated using:

\[ N = mg \]

Where:
- \( m \) is the mass (35 kg)
- \( g \) is the acceleration due to gravity (9.8 m/s²)

Calculate \( N \):

\[ N = 35 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 343 \, \text{N} \]

Now, calculate the coefficient of friction \( \mu \):

\[ \mu = \frac{30 \, \text{N}}{343 \, \text{N}} ≈ 0.0875 \]

By rounding, we find that the coefficient of friction is closest to option (b) 0.087.

**Answer:**
(b) 0.087

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