If a = , find the solutions of this equation for the mag- the figure) can be described by F = A(cos bt– a cos 3bt), where t is time in seconds, A > 0, b> 0, and 0 < a < 1 EXERCISE 82 OF (a) Show that F = 0 when t = –T/(2b) and t = T/(26). (The time t = -/(2b) corresponds to the moment when the foot first touches the ground and the weight of the body is being supported by the other foot.) %3D (b) The maximum force occurs when 3a sin 3bt = sin bt. %3D interval –/(2b)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3, express the maximum force in terms of A.
tions
If a = , find the solutions of this equation for the
mag-
82 Force of a foot When an individual is walking, the
the figure) can be described by
F = A(cos bt - a cos 3bt),
%D
where t is time in seconds, A > 0, b > 0, and 0 < a < 1
EXERCISE 82
F.
(a) Show that F = 0 when t = –T/(2b) andt = T
(The time t = -T/(2b) corresponds to the moment
when the foot first touches the ground and the weight of
the body is being supported by the other foot.)
/(2b).
%3D
(b) The maximum force occurs when
3a sin 3bt = sin bt.
If a =
interval -7/(2b) < t< T/(2b).
(c) If a = 3, express the maximum force in terms of A.
Transcribed Image Text:3, express the maximum force in terms of A. tions If a = , find the solutions of this equation for the mag- 82 Force of a foot When an individual is walking, the the figure) can be described by F = A(cos bt - a cos 3bt), %D where t is time in seconds, A > 0, b > 0, and 0 < a < 1 EXERCISE 82 F. (a) Show that F = 0 when t = –T/(2b) andt = T (The time t = -T/(2b) corresponds to the moment when the foot first touches the ground and the weight of the body is being supported by the other foot.) /(2b). %3D (b) The maximum force occurs when 3a sin 3bt = sin bt. If a = interval -7/(2b) < t< T/(2b). (c) If a = 3, express the maximum force in terms of A.
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