If a field K is algebraically closed, then every polymomiel with co- efficients in k has a root in K. © True. This is an equiral ent way of statling the defiaition of in algebiuically closed field. O True. If K is algebraically closed, theen every equation hos a solution in K, so eve ry polymomiel has a root in K. O False. This only applies to non-consbant poly nomicls. A nonzeu constant polynomiel such as 1 does not hove a root in K. O False. For example, the polynomisl T k-W +1 does not dEK have a root in K,
If a field K is algebraically closed, then every polymomiel with co- efficients in k has a root in K. © True. This is an equiral ent way of statling the defiaition of in algebiuically closed field. O True. If K is algebraically closed, theen every equation hos a solution in K, so eve ry polymomiel has a root in K. O False. This only applies to non-consbant poly nomicls. A nonzeu constant polynomiel such as 1 does not hove a root in K. O False. For example, the polynomisl T k-W +1 does not dEK have a root in K,
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Which option is correct. THERE IS ONLY 1 CORRECT option. a,b,c or d!
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