If a charged sphere has a surface charge density of o= k cos 0 glued over its surface (where k is a constant and is the usual polar angle), then the exact potential outside the sphere is kR³ 1 360 r2 which can be derived using the method of separation of variables. V(r, 0) = cos r>R,
If a charged sphere has a surface charge density of o= k cos 0 glued over its surface (where k is a constant and is the usual polar angle), then the exact potential outside the sphere is kR³ 1 360 r2 which can be derived using the method of separation of variables. V(r, 0) = cos r>R,
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Question
Find the approximate electrostatic potential, at points far from the sphere, and compare it to
the exact answer given above. What can you conclude about the higher multipoles?
![If a charged sphere has a surface charge density of
o = k cos 0
glued over its surface (where k is a constant and is the usual polar angle), then the exact potential
outside the sphere is
V(r, 0)
kR³ 1
3€0 r2
which can be derived using the method of separation of variables.
Cos 0
r≥ R,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa19a6abe-3b19-4c4d-aaff-322af5c5797a%2Fab90e5e3-c78f-4c76-8c76-5d7cbf74fe8a%2Fdy20yqu_processed.png&w=3840&q=75)
Transcribed Image Text:If a charged sphere has a surface charge density of
o = k cos 0
glued over its surface (where k is a constant and is the usual polar angle), then the exact potential
outside the sphere is
V(r, 0)
kR³ 1
3€0 r2
which can be derived using the method of separation of variables.
Cos 0
r≥ R,
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